SAT Math Part 1 - Evaluating Functions and Solving Basic Equations - Algebra - By The Organic Chemistry Tutor
Transcript
00:0-1 | this video is for those of you who are studying | |
00:02 | for the S . A . T . Exam , | |
00:04 | it's going to focus on the math section of that | |
00:07 | exam . Now this is just part one . So | |
00:10 | be sure to check out the links in the description | |
00:12 | section below for part two . Now this particular video | |
00:16 | is going to focus on evaluating functions and solving equations | |
00:20 | in future videos , I'm going to talk about trigonometry | |
00:25 | , geometry problems , converting sentences into equations , averages | |
00:29 | proportions , fractions percent and other topics that you're going | |
00:34 | to be tested on . But let's focus on this | |
00:37 | section of the S . A . T . Exam | |
00:40 | . So let's start with number one by the way | |
00:42 | for each of these problems , pause the video , | |
00:45 | try it yourself and then once you have the answer | |
00:48 | , play the video to see if you have the | |
00:50 | right solution . Let's start with this problem . If | |
00:54 | G of X is equal to five X squared minus | |
00:58 | four X plus two X cube . Then what is | |
01:02 | G . F . So all we need to do | |
01:05 | is evaluate the function , We need to replace X | |
01:09 | with three . So instead of five X squared is | |
01:12 | going to be five times three squared And instead of | |
01:16 | four ax is gonna be four times street Now , | |
01:22 | 3 to the second power . It's basically multiplying 2 | |
01:26 | , 3 together . Three times three is 9 . | |
01:28 | four times 3 is 12 . Now what about 3 | |
01:32 | to the 3rd power ? So in this case we're | |
01:34 | multiplying three threes together three times 3 is nine . | |
01:39 | nine Times Street is 27 . So this is what | |
01:43 | we now have Now , five times 9 is 45 | |
01:51 | and two times 27 , two times 20 is 40 | |
01:55 | Two times seven is 14 , 40 plus 14 is | |
01:58 | 54 , 45 -12 is 33 And 33 plus 54 | |
02:07 | . It's 87 . So d . Is the right | |
02:12 | answer for this problem number two . In the function | |
02:17 | H of X shown below K is a constant . | |
02:22 | If HF three is 26 Then what is the value | |
02:26 | of H of -3 ? So notice that were given | |
02:33 | this information . That's going to be helpful in order | |
02:36 | for us to calculate the value of kate . Once | |
02:39 | we find the value of K We can replace X | |
02:42 | with -3 And we could find the value of H | |
02:45 | . of -3 . So focusing on this expression what | |
02:54 | is exe X is the number inside of the function | |
02:58 | ? So accessory , That means h . of X | |
03:02 | will be 26 . So let's begin by replacing X | |
03:06 | with three . So this is gonna be 5/3 time | |
03:11 | straight squared plus K . Time Stream -4 . Now | |
03:16 | H . Of three that's equal to 26 . So | |
03:19 | let's replace H . Of three with 26 now 5/3 | |
03:26 | times three squared three squared is nine . So we | |
03:30 | have this so far . Now if you want to | |
03:33 | you can add for to both sides so these will | |
03:36 | cancel . And so we have 26 plus four which | |
03:39 | is 30 now what about this ? 5/3 times nine | |
03:45 | . Now you could do five times nine divided by | |
03:48 | three . Or you could do nine divided by three | |
03:50 | times five . I prefer the second method nine divided | |
03:54 | by three history three times five is 15 . So | |
03:58 | now we have this Now let's subtract both sides by | |
04:02 | 15 . Yes So 30 -15 is 15 And that's | |
04:09 | going to equal three K . Now if we divide | |
04:12 | both sides by three K . I mean by three | |
04:15 | . Rather We get 15 divided by three which is | |
04:17 | five . So Kay is five . Now let's just | |
04:26 | write that here . So now that we have our | |
04:30 | K . Value we could answer the question what is | |
04:33 | the value of H . Of negative three ? So | |
04:38 | let's replace X with -3 . And Let's replace K | |
04:44 | with five negative three squared negative three times negative three | |
04:50 | is positive nine . five times negative three is negative | |
04:55 | 15 . nine divided by three is 3 . three | |
04:59 | times 5 is 15 . So we have 15 -15 | |
05:03 | and -4 . These two will cancel and so this | |
05:07 | will give us negative four . So H of negative | |
05:10 | three is negative four . So A is the right | |
05:13 | answer number three . If our vax is equal to | |
05:19 | three X squared plus four X . Monastery then which | |
05:23 | of the following expressions Is equivalent to our of -4 | |
05:28 | X . So for this problem we simply need to | |
05:32 | replace Acts with negative for Acts . So it's three | |
05:37 | times negative four X squared and then four instead of | |
05:41 | four X . We're going to replace Acts with negative | |
05:44 | four X . So it's just direct substitution . Now | |
05:49 | what is negative for X squared ? So this is | |
05:52 | basically negative four x Times another -4 x -4 times | |
05:59 | negative four is positive 16 X times X . He | |
06:03 | needs to add the exponents , one plus one is | |
06:05 | two . So we're going to get three . Yeah | |
06:11 | Times positive 16 x squared Now four times negative for | |
06:16 | that's negative 16 and we can carry over the X | |
06:22 | . Now the last thing we need to do is | |
06:23 | multiply three x 16 . three times 16 is 48 | |
06:29 | . So are of -4 x is equal two 48 | |
06:36 | X squared minus 16 . X minus tree . Therefore | |
06:40 | answer choice C . Is the correct answer number four | |
06:46 | . Consider the function G . Of X is equal | |
06:49 | to six over X plus C . What is the | |
06:53 | value of C ? If the point to come ? | |
06:56 | A seven lies on a graph of G Fx . | |
07:03 | So let's focus on The .2 comma seven . So | |
07:09 | that tells us that Access to Y is seven . | |
07:15 | So this means that GF two is equal to seven | |
07:19 | . So what we're going to do is we're going | |
07:21 | to replace X with seven in that function . So | |
07:24 | GF two , it's going to be 6/2 plus C | |
07:30 | . Now we know that GF two is equal to | |
07:33 | seven . So let's replace GF two of 7 . | |
07:36 | So we have seven is equal to six divided by | |
07:40 | two , which is three plus C . Now let's | |
07:44 | attract both sides by three . seven . Monastery is | |
07:47 | four . So in this problem we can see that | |
07:51 | C is equal to a value of for so D | |
07:55 | is the answer number five . Given the functions F | |
08:00 | of X and G of x , What is the | |
08:02 | value of G . 4 ? So let's plug in | |
08:06 | four into this expression . So it's gonna be four | |
08:11 | squared -2 times before minus five . Now four squared | |
08:18 | is 16 F . Before we need to plug it | |
08:21 | into that function . So it's going to be 3-4 | |
08:26 | And then replace X with four And then -2 . | |
08:32 | Now 3/4 times for the force will cancel . So | |
08:36 | that's just gonna give us 3 -2 . 3 -2 | |
08:42 | is one . and so we have 16 -2 which | |
08:46 | is 14 And 14 -5 is nine . So in | |
08:51 | this example G . F four has a value of | |
08:54 | nine which means E . is the right answer . | |
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09:24 | page . Also , when you get a chance to | |
09:27 | check out the links in the description section below this | |
09:29 | video , because I'm going to post some other resources | |
09:32 | that you might find helpful . So let's get back | |
09:36 | to the video number six . If G F X | |
09:40 | plus two is equal to X squared minus three X | |
09:43 | plus seven , Then what is the value of GF | |
09:47 | 5 ? Go ahead , take a minute and try | |
09:52 | this problem . Now , the first thing we need | |
09:54 | to determine is the value of X . What is | |
09:58 | X Is actually equal to 5 ? It turns out | |
10:03 | that in this problem is something else . We need | |
10:07 | to write G . 05 as being G Of three | |
10:11 | Plus 2 . The reason being is we have X-plus | |
10:16 | two inside of G . Yeah . So notice that | |
10:22 | the two is the same , which means that X | |
10:24 | has to be equal to three . So what we're | |
10:28 | going to do is we're going to replace acts with | |
10:30 | three in this problem . So it's going to be | |
10:32 | three squared minus three times three plus seven . three | |
10:37 | squared is nine , Three times three is also nine | |
10:40 | . And so these two numbers will cancel . Thus | |
10:44 | GF five is equal to seven . So in this | |
10:47 | problem you need to determine X based on what you | |
10:50 | see here . So what you could do is set | |
10:53 | five equal to X plus two . Subtract on both | |
10:56 | sides by two , You'll get that X . Is | |
10:59 | equal to three . And then once you have the | |
11:01 | X . Value , you can now plug it in | |
11:03 | to the formula or to the function rather . So | |
11:06 | for this problem answer choice D . Is the right | |
11:08 | answer number seven . What is the value of acts | |
11:13 | in the equation shown below ? So here we have | |
11:17 | two fractions separated by an equal sign . When you | |
11:21 | see this , you need to cross multiply . So | |
11:25 | for over seven times x Is the same as for | |
11:30 | X divided by seven . You can view this as | |
11:32 | X over one And this is equal to 8/5 . | |
11:39 | So first we're going to multiply four x by five | |
11:44 | And that's gonna give us 20 x . And then | |
11:47 | we're gonna multiply seven times eight , Which is 56 | |
11:53 | . Now let's divide both sides by 20 . So | |
11:57 | now we need to reduce the fraction , So how | |
12:01 | can we reduce 56/20 while both numbers are even , | |
12:06 | so We can divide the top and the bottom by | |
12:09 | two Half of 56 is 28 . Half of 20 | |
12:14 | is 10 . Now we still have even numbers , | |
12:18 | So we could divide both numbers again by two , | |
12:21 | 28 , divided by two is 14 , Half of | |
12:25 | 10 is five . So the answer is B 14/5 | |
12:33 | . Number eight . If three times y plus four | |
12:38 | plus five Times two Y . Monastery is equal To | |
12:44 | 10 y plus three . Then what is the value | |
12:48 | of Why ? So in this equation all we need | |
12:52 | to do is simply soft . So let's rewrite the | |
12:57 | equation first . Now the first thing you need to | |
13:07 | do is distribute let's distribute three to why and to | |
13:12 | four three times . Why is street wide three Times | |
13:17 | Voice 12 . Now let's do the same thing with | |
13:21 | the five . So we have five times to why | |
13:25 | ? That's 10 y . five times 3 is 15 | |
13:32 | . If we subtract both sides by 10 Y , | |
13:35 | the bees will cancel . Now We can combine like | |
13:39 | terms 12 plus negative 15 , That's going to be | |
13:45 | -3 . So this is what we now have . | |
13:49 | Now Let's add 3 to both sides . 3-plus 3 | |
13:55 | is six . Our next step is to divide both | |
14:00 | sides by three . six , divided by three is | |
14:04 | too So why Is equal to 2 ? Which means | |
14:09 | B is the right answer number nine A four x | |
14:15 | plus seven Is equal to 31 . Then what is | |
14:19 | the value of 5 ? X -8 ? So what | |
14:24 | we need to do in this problem is we need | |
14:26 | to solve for X in this equation . Now once | |
14:30 | we have the value of X We can plug it | |
14:33 | in into that expression . And let's calculate the value | |
14:36 | of five X -8 . So let's start with this | |
14:42 | equation , Let's begin by subtracting both sides by seven | |
14:50 | . 31 -7 is 24 . Next Let's divide both | |
14:54 | sides by four . So 24 divided by four is | |
14:59 | 6 . So now that we have the value of | |
15:02 | X , let's plug it into that expression . So | |
15:06 | we have five X -8 . So it's gonna be | |
15:09 | five times 6 -8 . five times 6 is 30 | |
15:14 | And 30 -8 is 22 . So answer choice is | |
15:19 | the right answer number nine , A four X plus | |
15:24 | seven is equal to 31 . Then what is the | |
15:28 | value of 5 ? X modest 8 ? So we're | |
15:32 | given a linear equation and an algebraic expression . What | |
15:38 | we need to do is calculate the value of X | |
15:41 | by solving the linear equation . And then once we | |
15:45 | have that , once we have the value of X | |
15:48 | we could plug it in to the algebraic expression . | |
15:52 | And that's going to give us the value Of five | |
15:55 | X -8 . So let's begin by solving the equation | |
16:01 | on the left . The first thing we need to | |
16:04 | do is some try both sides by seven . Mhm | |
16:09 | . 31 -7 is 24 . Next We need to | |
16:14 | divide both sides by four . 24 , divided by | |
16:19 | four is 6 . So X Is equal to six | |
16:25 | . Now let's take that value and plug it into | |
16:28 | this expression . So let's replace X with six . | |
16:34 | five times 6 is 30 And 30 -8 is 22 | |
16:40 | . So therefore answer choice A . Is the correct | |
16:45 | answer number 10 . Given the equation shown below , | |
16:52 | what is the value of 12 divided by X plus | |
16:57 | Torri . Now this problem is very similar to the | |
17:01 | last problem . Were given an equation in which we | |
17:05 | need to solve and once we get the value of | |
17:08 | X , we need to plug it into this expression | |
17:11 | to calculate the value of 12 over X plus three | |
17:18 | . Now , how should we solve this particular equation | |
17:23 | ? What do you think we need to do Whenever | |
17:26 | you see two fractions separated by an equal sign , | |
17:31 | you need to cross multiply . So we're gonna multiply | |
17:35 | too By four x -9 And then we're gonna multiply | |
17:40 | three By X- Plus four . So let's distribute to | |
17:47 | two , X -9 . So two times 4 x | |
17:51 | is a tax and then two times negative nine . | |
17:56 | That's going to be negative 18 On the right side | |
18:00 | we have three times acts And three times 4 , | |
18:04 | which is 12 . Now let's subtract both sides by | |
18:09 | three X and at the same time Let's add 18 | |
18:14 | to both sides . So these will cancel now . | |
18:20 | eight x monastery x is five x . 12 plus | |
18:25 | 18 is 30 . Now , our next step is | |
18:29 | to divide both sides by five , 30 divided by | |
18:33 | five is 6 , so X is equal to six | |
18:39 | . Now that we have the value of X , | |
18:43 | we can take it and plug it into that expression | |
18:47 | . So this is going to be 12 Over 6-plus | |
18:51 | 3 . 12 divided by six is too two Plus | |
18:56 | 3 is five . So as we can see here | |
19:01 | , answer choice is the correct answer . So that's | |
19:04 | basically it for this video . Now , be sure | |
19:07 | to check out the links in the description below . | |
19:10 | As I'm going to post part two at that location | |
19:13 | when it's available . Thanks for watching . |
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SAT Math Part 1 - Evaluating Functions and Solving Basic Equations - Algebra is a free educational video by The Organic Chemistry Tutor.
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