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Prove the slope criteria G-GPE.5 Question & Answer Key Resources Lumos StepUp High School Integrated Mathematics 2 - Workbooks and Online Assessments

Lumos StepUp High School Integrated Mathematics 2 - Workbooks and Online Assessments Prove the slope criteria

Get Full Access to Lumos StepUp High School Integrated Mathematics 2 - Workbooks and Online Assessments

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Mary finds the equation of the line that contains the points (-2, 5) and (4, 0) as shown below. Finds her mistake(s) and states the correct equation.
\(m = \frac{y_2-\ y_1}{x_2-x_1}\)
\(m = \frac{0-5}{4-2}\)
\(m = -\frac{5}{2}\)
y = mx + b
\(y = -\frac{5}{2}x+4\)

Question Type: Extended Constructed Response

Standard(s):HSG.GPE.B.5

Standard Description: Prove the slope criteria for parallel and perpendicular lines and use them to solve geometric problems (e.g., find the equation of a line parallel or perpendicular to a given line that passes through a given point).

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Prove the slope criteria G-GPE.5 Question & Answer Key Resources Lumos StepUp High School Integrated Mathematics 2 - Workbooks and Online Assessments

Lumos StepUp High School Integrated Mathematics 2 - Workbooks and Online Assessments Prove the slope criteria

Get Full Access to Lumos StepUp High School Integrated Mathematics 2 - Workbooks and Online Assessments

Buy ACTASPIRE Practice Resources

Mary finds the equation of the line that contains the points (-2, 5) and (4, 0) as shown below. Finds her mistake(s) and states the correct equation.\(m = \frac{y_2-\ y_1}{x_2-x_1}\)\(m = \frac{0-5}{4-2}\)\(m = -\frac{5}{2}\)y = mx + b\(y = -\frac{5}{2}x+4\)

Question Type: Extended Constructed Response

Standard(s):HSG.GPE.B.5

Standard Description: Prove the slope criteria for parallel and perpendicular lines and use them to solve geometric problems (e.g., find the equation of a line parallel or perpendicular to a given line that passes through a given point).

Ratings

Mary finds the equation of the line that contains the points (-2, 5) and (4, 0) as shown below. Finds her mistake(s) and states the correct equation.
\(m = \frac{y_2-\ y_1}{x_2-x_1}\)
\(m = \frac{0-5}{4-2}\)
\(m = -\frac{5}{2}\)
y = mx + b
\(y = -\frac{5}{2}x+4\)