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Matthew was asked to solve \(64x^2+16 x-3=0\) using the method of "Complete the Square'' and his work is shown below. Did he solve it correctly, yes or no? Why?
\(64x^2+16x-3=0\)
\((8x+3)(8x-1)=0\)
\(8x+3=0\ \ \ \ \ \ \ \ \ \ 8x-1=0\)
\(8x=\ -3\ \ \ \ \ \ \ \ \ \ \ \ \ 8x=1\)
\(x=\ \frac{-3}{8}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x=\ \frac{1}{8}\)
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